π = 9801 2 2 ∑ n = 0 ∞ ( 4 n ) ! ( n ! ) 4 × [ 1103 + 26390 n ] ( 4 × 99 ) 4 n {\displaystyle \pi ={\frac {9801}{2{\sqrt {2}}\displaystyle \sum _{n=0}^{\infty }{\frac {(4n)!}{(n!)^{4}}}\times {\frac {[1103+26390n]}{(4\times 99)^{4n}}}}}}
![{\displaystyle \pi ={\frac {9801}{2{\sqrt {2}}\displaystyle \sum _{n=0}^{\infty }{\frac {(4n)!}{(n!)^{4}}}\times {\frac {[1103+26390n]}{(4\times 99)^{4n}}}}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/0ff69018803625bc5b3d88da7f0e0c02ce732959)
